Tungsten Weight Calculator

You’re fabricating a counterweight for a piece of construction equipment, or designing a compact radiation-shielding insert for a jobsite inspection enclosure. Space is tight, and steel would be too bulky. Tungsten is the go-to because it packs a lot of mass into a small volume—but that also means a small dimension change can swing the weight dramatically. A tungsten weight calculation helps you estimate handling needs, shipping class, lifting points, and whether a part will exceed a bracket’s load rating before anything gets cut.

What Is a Tungsten Weight Calculator?

The calculation is fundamentally:

Weight = Density × Volume

For tungsten, the density used here is 1,204 lb/ft³ (an engineering-friendly density in imperial units). The calculator reports results in both pounds and kilograms, and it supports common shapes such as flat plate, round bar, square bar, hollow tube, and solid cylinder.

Context check: tungsten is extremely dense—roughly 1.7 times as dense as lead and about 2.5 times as dense as steel (by typical reference values). That’s why tungsten parts can be surprisingly heavy even when they look small.

The Formula (Step by Step)

Step 1: Compute volume in cubic inches (in³) Different shapes use different volume equations:

- Plate/Block (rectangular prism): Volume_in3 = Length × Width × Thickness

- Round bar / solid cylinder: Volume_in3 = π × (Diameter/2)² × Length

- Square bar: Volume_in3 = Width² × Length

- Hollow tube / pipe (ring area × length): Volume_in3 = π × [(OD/2)² − (ID/2)²] × Length where ID = OD − 2 × WallThickness

Step 2: Convert cubic inches to cubic feet Volume_ft3 = Volume_in3 / 1,728 (There are 1,728 in³ in 1 ft³.)

Step 3: Multiply by tungsten density Weight_lbs = Density_lb_ft3 × Volume_ft3 Weight_lbs = 1,204 × Volume_ft3

Step 4: Convert pounds to kilograms (optional) Weight_kg = Weight_lbs × 0.453592

Metric input note: If dimensions are entered in centimeters or millimeters, they must be converted to inches before using the formulas above (because the density is in lb/ft³ and the intermediate volume is in in³). Common conversions: - Inches = centimeters / 2.54 - Inches = millimeters / 25.4

Authoritative context: unit conversions and density/weight relationships are standard engineering fundamentals; NIST provides the basis for SI/US customary conversions and measurement consistency (Gold source: NIST, .gov).

Worked Examples (with Real Numbers)

### Example 1: Flat plate insert (imperial inputs) A tungsten plate is 6 in long, 2 in wide, and 0.25 in thick.

1) Volume in cubic inches Volume_in3 = Length × Width × Thickness Volume_in3 = 6 × 2 × 0.25 = 3.0 in³

2) Convert to cubic feet Volume_ft3 = 3.0 / 1,728 = 0.001736 ft³

3) Weight in pounds Weight_lbs = 1,204 × 0.001736 = 2.09 lb (rounded)

4) Weight in kilograms Weight_kg = 2.09 × 0.453592 = 0.95 kg (rounded)

Takeaway: a small-looking plate can still be around 2.1 lb—useful when designing compact ballast or trim weights.

### Example 2: Round bar/rod (metric inputs converted) A tungsten rod is 30 cm long with a 2.0 cm diameter.

Convert to inches: - Length_in = 30 / 2.54 = 11.811 in - Diameter_in = 2.0 / 2.54 = 0.7874 in Radius_in = 0.7874/2 = 0.3937 in

1) Volume in cubic inches Volume_in3 = π × r² × L Volume_in3 = π × (0.3937)² × 11.811 (0.3937)² = 0.1550 π × 0.1550 = 0.4869 0.4869 × 11.811 = 5.75 in³ (approx)

2) Convert to cubic feet Volume_ft3 = 5.75 / 1,728 = 0.00333 ft³

3) Weight in pounds Weight_lbs = 1,204 × 0.00333 = 4.01 lb

4) Weight in kilograms Weight_kg = 4.01 × 0.453592 = 1.82 kg

Takeaway: a 30 cm rod under 1 inch in diameter can still be about 4 lb—important for handling, packaging, and fastener selection.

### Example 3: Hollow tube (pipe) for a weighted sleeve A tungsten tube is 10 in long, with 1.50 in outside diameter (OD) and 0.125 in wall thickness.

Compute inside diameter: - ID = OD − 2 × WallThickness - ID = 1.50 − 2 × 0.125 = 1.25 in OD radius = 1.50/2 = 0.75 in ID radius = 1.25/2 = 0.625 in

1) Cross-sectional area (ring) in in² Area = π × (R_OD² − R_ID²) R_OD² = 0.75² = 0.5625 R_ID² = 0.625² = 0.390625 Difference = 0.171875 Area = π × 0.171875 = 0.5396 in²

2) Volume in in³ Volume_in3 = Area × Length = 0.5396 × 10 = 5.396 in³

3) Convert to ft³ Volume_ft3 = 5.396 / 1,728 = 0.00312 ft³

4) Weight Weight_lbs = 1,204 × 0.00312 = 3.76 lb Weight_kg = 3.76 × 0.453592 = 1.71 kg

Takeaway: hollowing the part reduces weight, but it’s still heavy; this matters when designing sleeves that slide over shafts or posts.

Pro Tip (common fabrication reality): If the part will be sintered, brazed, or made from a tungsten alloy (not pure tungsten), density can vary. For tight tolerance weight targets, confirm the supplier’s certified density and adjust the density value accordingly.

Common Mistakes to Avoid (and How to Fix Them)

2) Using wall thickness incorrectly for tubes A frequent error is subtracting wall thickness once instead of twice. Inside diameter must be: ID = OD − 2 × WallThickness Otherwise, the tube volume is overstated and the weight comes out too high.

3) Confusing thickness vs. height for rectangular shapes For plates/blocks, volume is Length × Width × Thickness. If “height” is used instead of thickness, make sure it represents the third dimension of the prism.

4) Forgetting the in³ to ft³ conversion Density is per cubic foot, so volume must be in ft³. Skipping: Volume_ft3 = Volume_in3 / 1,728 will produce a weight that’s 1,728 times too large.

Standards/context note: when weights affect lifting, rigging, or handling plans, follow applicable safety standards (for example, OSHA regulations for material handling and rigging practices in the US; local equivalents elsewhere). Even if calculations are correct, field practice should include rated hardware, inspection, and safety factors.

When to Use This Calculation (and When Manual Math Is Enough)

Manual math is enough when you have one simple shape and you’re comfortable with unit conversions. A calculator-style workflow is better when you’re iterating multiple shapes, switching between metric and imperial drawings, or checking several what-if dimensions quickly—especially because tungsten’s high density makes small mistakes expensive and potentially unsafe.

Weight (lbs) = Volume (ft³) × 1,204 lb/ft³

Weight (kg) = Volume (m³) × 19,250 kg/m³

Volume (rectangular) = Length × Width × Height

Volume (cylindrical) = π × radius² × height

• DOE — Energy Saver
• USDA Forest Products Laboratory
• EPA — Energy Resources
• USGS — Science for a Changing World
• NIST — Weights and Measures